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Czech 2.5x5mm SuperDuo Beads, Opaque Violet Picasso, 10 g

Part Number:DU0523020-43400
Czech 2.5x5mm SuperDuo Beads, Opaque Violet Picasso, 10 g
In Stock, Ships Immediately!
Your Price: $2.99
On sale$1.99 On Sale

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Sold As:

10 g

Country of Origin:

Czech Republic

Size:

02.5mm x 5mm

Material:

Glass

Shape:

SuperDuo

Finish

Hole Size:

0.8mm

Bin:

H1-145
Czech Glass 2.5x5mm SuperDuo Beads, Opaque Violet Picasso, 10 Grams
  • Material: Czech Glass
  • Dimensions: 2.5mm wide by 5mm long
  • Hole size: 0.8mm
  • Number of beads per 10 gram pack: Approx. 140
  • Number of beads per inch: About 9

Customer Reviews

5 Stars
Can't wait to use these beads!
These beads are for a bracelet I want to make. They are very good quality. Delivery was pretty quick.
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Reviewed by:  from Lithonia. on 3/18/2015
5/5
5 Stars
superduo
what an unusual color. They're going to be fun to put with some gold metallic beads. cool beads.
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Reviewed by:  from Lakeview, AR. on 1/21/2015
5/5
4 Stars
Czech Glass 2.5x5mm SuperDuo Beads, Opaque Violet Picasso, 10 grams
I was a bit disappointed that the beads didn't have more violet color in them. However, I'll have to wait to actually use them to see how well they would look in a jewelry project. So, at this time I can't give a fair review until I do so.
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Reviewed by:  from Vallejo, CA. on 1/8/2015
4/5
5 Stars
Super Duos Opaque Violet Picasso
Very pretty!
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Reviewed by:  from OR. on 11/4/2014
5/5
5 Stars
SuperDuo
The SuperDuos were all and much more than I expected from auntiesbeads. I have already started a project and the beads look fantastic.
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Reviewed by:  from Maryland. on 6/7/2014
5/5

Questions and Answers

Q: Hi, Are you sure this is the correct image for this product? It says opaque "violet" Picasso....looks more like copper color....just wondering!
Asked by: Francine Michaud - 12/18/2014
A: Czech glass colors are unique and named maybe for the process as well as the colors. I believe it must have started out as violet and then when the finishes were added that this is what it came out to be.
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Answer provided by:  Karla Schafer (12/22/2014)
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