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14kt Gold Filled Beading Chain By the Foot, 0.7mm

Part Number:GF/166/F
14kt Gold Filled Beading Chain By the Foot, 0.7mm
In Stock, Ships Immediately!
Your Price:$9.49

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Get 6 point(s) per unit purchased!
What's this?

Sold As:

Foot

Size:

0.7mm

Material:

Gold Filled

Shape:

Round

Bin:

X2-200

14 karat gold filled beading chain by the foot, 0.7mm. For use with end cap for beading chain. Priced per foot.
 


Lead and nickel free.

Customer Reviews

5 Stars
14kt Gold Filled Beading Chain By the Foot, 0.7mm
Glad to find this g/f chain. My daughter prefers it to silver and wanted me to make a floating bead 3-strand necklace for her. The 0.7mm is the perfect size for the beads and the g/f 2x2 crimp beads also purchased will secure the beads onto the chain. Plan on ordering more to have on hand for when she wants something else made.
Did you find this helpful?  1 of 1 Found Helpful
Reviewed by:  from West Chester, OH. on 2/18/2015
5/5
5 Stars
Gold Filled Beading Chain
I needed a chain to put my gold heart on, this is a perfect fit.
Did you find this helpful?  1 of 1 Found Helpful
Reviewed by:  from Ohio . on 6/21/2012
5/5
4 Stars
Gold Filled Beading Chain By the Foot, 0.7 mm
So happy to find this item. I can find the silver locally but not gold filled.
Did you find this helpful?  1 of 1 Found Helpful
Reviewed by:  from Broken Arrow, OK 74012. on 3/26/2012
4/5
5 Stars
great
Loved it.
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Reviewed by:  from Paulden. on 5/7/2015
5/5

Questions and Answers

Q: What is your estimate of total weight in beads that is appropriate for this chain in combination with the gold-filled chain crimp ends?
Asked by: ab - 11/8/2013
A: Though I am not clear on how much the beading chain will hold, it's purpose is more of an aesthetic one much to be used as you would a mono-filament material in illusion style necklaces, it should be okay to hold several beads, but not completely strung as beading wire. I would trust that more to a link type chain, to ensure the hold on the ends.

Karla
Was this answer helpful?  1 of 1 Customer(s) found this Answer helpful.
Answer provided by:  Adam Henderson (11/8/2013)

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